J.P. Losman will remain the starting quarterback for the Buffalo Bills. At least for one more game.
Bills coach Dick Jauron announced Tuesday that the team was sticking with Losman. Jauron did not say if Losman would stay in the lineup beyond Sunday's game at the Miami Dolphins.
Rookie Trent Edwards had been awarded the job because of his solid play in three starts after Losman suffered a sprained knee in the Bills' third game at New England.
But Edwards sprained his right wrist in the second half against the New York Jets two weeks ago, opening the door for Losman's return.
Losman came off the bench to lead Buffalo to 10 points in three possessions, including an 85-yard touchdown pass to receiver Lee Evans, a 13-3 win over the Jets.
Losman followed that up by guiding the Bills to their biggest offensive output of the season in a 33-21 victory over the Cincinnati Bengals. Losman threw for 295 yards, the third most of his career, and the Bills' 479 total yards were the most in a game in five years.
Jauron cited Losman's performance the last two weeks as a factor in the decision.
"He did an outstanding job finishing the Jets game and in leading us to victory over the Bengals this past Sunday," Jauron said in a release.
It is not known if Edwards' wrist has recovered enough to play. He was inactive against the Bengals because of persistent soreness and swelling. Jauron is expected to update Edwards' status today.
Losman will get a chance to strengthen his case to stay in the starting lineup on Sunday against the winless Dolphins, who have one of the worst defenses in the NFL. Another strong game will make it difficult for Jauron to bench Losman again, especially with a Sunday night home game against the unbeaten New England Patriots looming.
Despite the quarterback carousel, the Bills (4-4) have won three straight and four of their last five games to get themselves into playoff contention.